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SSC Sample Paper Mock Test-10 SSC CGL Tear-II Paper-1

  • question_answer
    Tap 'A' can fill the cistern in 5 h and the another tap 'B' can empty that cistern in 4 h. How much time it will take to empty the cistern if both the taps are opened simultaneously when the cistern is already full?

    A)  10 h    

    B)  16 h   

    C)  18 h    

    D)  20 h

    Correct Answer: D

    Solution :

    The part of cistern which can be filled in \[1\,\,\text{h}=\frac{1}{5}\] When the part of cistern which can be emptied in\[1\,\,\text{h}=\frac{1}{4}\] While both the taps are opened, cistern part can be emptied in\[1\,\,\text{h}=\frac{1}{4}-\frac{1}{5}=\frac{5-4}{20}=\frac{1}{20}\] Therefore, the required time to empty the cistern is 20 h.


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