A) 8
B) 6
C) 5
D) 4
Correct Answer: D
Solution :
Let number be x. \[\therefore \] According to question, \[{{x}^{3}}-{{x}^{2}}=48\] \[{{x}^{2}}\,\,(x-1)=48\] \[{{x}^{2}}\,\,(x-1)=16\times 3\] \[{{x}^{2}}=16\] \[\Rightarrow \] \[x=4\] or \[(x-1)=3\] \[\Rightarrow \] \[x=3+1\] \[x=4\]You need to login to perform this action.
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