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SSC Sample Paper Mock Test-10 SSC CGL Tear-II Paper-1

  • question_answer
      In  a  quadrilateral  ABCD, \[\angle B=90{}^\circ \] and \[A{{D}^{2}}=A{{B}^{2}}+B{{C}^{2}}+C{{D}^{2}}.\] Then, \[\Delta ADC\] is

    A)  equilateral triangle

    B)  isosceles

    C)  right angled triangle

    D)  None of these

    Correct Answer: C

    Solution :

    Here,     \[A{{D}^{2}}=A{{B}^{2}}+B{{C}^{2}}+C{{D}^{2}}\] \[A{{D}^{2}}=A{{C}^{2}}+D{{C}^{2}}\] \[\therefore \]\[\Delta ACD\]is a right angled triangle.


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