A) \[-\,\,6,\,\,-2\]
B) \[-\,\,5,4\]
C) \[-\,\,2,6\]
D) \[2,6\]
Correct Answer: D
Solution :
| Taking first two parts, we get |
| \[\frac{x+y-8}{2}=\frac{x+2y-14}{3}\] |
| \[\Rightarrow \] \[3\,\,(x+y-8)=2\,\,(x+2y-14)\] |
| \[\Rightarrow \] \[3x+3y-24=2x+4y-28\] |
| \[\Rightarrow \] \[x-y=-\,\,4\] ?(i) |
| Taking last two parts, we get |
| \[\frac{x+2y-14}{3}=\frac{3x+y-12}{11}\] |
| \[\Rightarrow \] \[11\,\,(x+2y-14)=3(3x+y-12)\] |
| \[\Rightarrow \] \[11x+22y-154\] |
| \[=9x+3y-36\] |
| \[\Rightarrow \] \[2x+19y=118\] ?(ii) |
| Multiplying Eq. (i) by 2 and subtracting from Eq. (ii), we get \[21y=126\] |
| \[\Rightarrow \] y = 6 |
| Putting y = 6 in Eq. (i), we get x = 2. |
| \[\therefore \] \[x=2,\]\[y=6\] |
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