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SSC Sample Paper Mock Test-10 SSC CGL Tear-II Paper-1

  • question_answer
    The value of\[\sqrt{\frac{{{(0.1)}^{2}}+{{(0.01)}^{2}}+{{(0.009)}^{2}}}{{{(0.01)}^{2}}+{{(0.001)}^{2}}+{{(0.0009)}^{2}}}}\]is equal to

    A)  1

    B)  10

    C)  100

    D)  0.1

    Correct Answer: B

    Solution :

    \[\sqrt{\frac{{{(0.1)}^{2}}+{{(0.01)}^{2}}+{{(0.009)}^{2}}}{{{(0.01)}^{2}}+{{(0.001)}^{2}}+{{(0.0009)}^{2}}}}\] \[=\sqrt{\frac{0.01+0.0001+0.000081}{0.0001+0.000001+0.00000081}}\] \[=\sqrt{\frac{0.010181}{0.00010181}}=\sqrt{\frac{10181\times 100}{10181}}=\sqrt{100}=10\]


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