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SSC Sample Paper Mock Test-11 SSC CGL Tear-II Paper-1

  • question_answer
    The numbers 2272 and 875 are divided by a 3-digit number N, giving the same remainders. The sum of the digits of N is

    A) 10

    B)  11      

    C)  12

    D)  13

    Correct Answer: A

    Solution :

    Let the remainder in each case be x. Then, \[(2272-x)\] and \[(875-x)\] are exactly divisible by that three digit number. Hence, their difference \[[(2275-x)-(875-x)]\] = 1397 will also be exactly divisible by the said divisor (N). Now, \[1397=11\times 127\] Since, both 11 and 127 are prime numbers, Nis 127. \[\therefore \]Sum of digits \[=1+2+7=10\]


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