A) \[110{}^\circ \]
B) \[85{}^\circ \]
C) \[70{}^\circ \]
D) \[95{}^\circ \]
Correct Answer: A
Solution :
\[\angle LEB=35{}^\circ \] \[\angle FEB=2\times \angle LEB=70{}^\circ \] \[\angle AEB=\angle AEF+\angle BEF=180{}^\circ \] \[\Rightarrow \] \[\angle AEF=180{}^\circ -70{}^\circ =110{}^\circ \] \[\angle CFQ=\angle AEQ=110{}^\circ \](Alternate angles)You need to login to perform this action.
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