A) \[-\,\,2\]
B) \[-\,\,1\]
C) 0
D) 1
Correct Answer: B
Solution :
We know that \[{{a}^{0}}=1\] \[\therefore \]\[{{a}^{2x+2}}=1\]\[\Rightarrow \]\[2x+2=0\]\[\Rightarrow \]\[x=\frac{-\,\,2}{2}=-1\]You need to login to perform this action.
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