A) \[\frac{1}{9}\]
B) \[\frac{2}{9}\]
C) \[\frac{7}{9}\]
D) \[\frac{8}{9}\]
Correct Answer: B
Solution :
Volume of earth taken out \[=\pi {{r}^{2}}h\] \[=\frac{22}{7}\times 2\times 2\times 56=704\,\,{{\text{m}}^{3}}\] Volume of the ditch \[=48\times 16.5\times 4\,\,{{\text{m}}^{3}}=3168\,\,{{\text{m}}^{3}}\] Part of the ditch filled \[=\frac{704}{3168}=\frac{2}{9}\]
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