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SSC Sample Paper Mock Test-11 SSC CGL Tear-II Paper-1

  • question_answer
    A student walks from his house at a Speed of \[2\frac{1}{2}\text{km/h}\] and reaches his school 6 min late. The next day he increase his speed by 1 km/h and reaches 6 min before school time. How far is the school from his house?

    A)  \[\frac{5}{4}\,\,\text{km}\]

    B)  \[\frac{7}{4}\,\,\text{km}\]

    C)  \[\frac{9}{4}\,\,\text{km}\]

    D)  \[\frac{11}{4}\,\,\text{km}\]

    Correct Answer: B

    Solution :

    Let required distance be = x km
    Difference of time\[=6+6=12\]min\[=\frac{1}{5}\]h
    According to the question, \[\frac{x}{\frac{5}{2}}-\frac{x}{\frac{7}{2}}=\frac{1}{5}\]
    \[\Rightarrow \]\[\frac{2x}{5}-\frac{2x}{7}=\frac{1}{5}\]\[\Rightarrow \]\[\frac{14x-10x}{35}=\frac{1}{5}\]\[\Rightarrow \]\[\frac{4x}{35}=\frac{1}{5}\]
    \[\Rightarrow \]               \[x=\frac{35}{20}=\frac{7}{4}\text{km}\]


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