A) 38
B) 36
C) 34
D) 30
Correct Answer: C
Solution :
\[\because \]\[x=3+\sqrt{8}\] \[\therefore \]\[\frac{1}{x}=\frac{1}{3+\sqrt{8}}=\frac{3-\sqrt{8}}{(3+\sqrt{8})(3-\sqrt{8})}\] \[=\frac{3-\sqrt{8}}{9-8}=3-\sqrt{8}\] Now, \[{{x}^{2}}+\frac{1}{{{x}^{2}}}={{\left( x+\frac{1}{x} \right)}^{2}}-2\] \[={{(3+\sqrt{8}+3-\sqrt{8})}^{2}}-2\] \[=36-2=34\]You need to login to perform this action.
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