A) 10
B) 11
C) 12
D) 13
Correct Answer: A
Solution :
Let the remainder in each case be x. Then, \[(2272-x)\] and \[(875-x)\] are exactly divisible by that three digit number. Hence, their difference \[[(2275-x)-(875-x)]\] = 1397 will also be exactly divisible by the said divisor (N). Now, \[1397=11\times 127\] Since, both 11 and 127 are prime numbers, Nis 127. \[\therefore \]Sum of digits \[=1+2+7=10\]You need to login to perform this action.
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