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SSC Sample Paper Mock Test-11 SSC CGL Tear-II Paper-1

  • question_answer
    A liquid 'P' is \[1\frac{3}{7}\] times as heavy as water and water is \[1\frac{2}{3}\] times as heavy as another liquid 'Q'. The amount of liquid 'P' that must be added to 7 L of the liquid 'Q' so that the mixture may weight as much as an equal volume of water, will be

    A) 7 L 

    B)  \[5\frac{1}{6}\text{L}\]

    C)  5 L

    D)  \[4\frac{2}{3}\text{L}\]

    Correct Answer: D

    Solution :

    Let x litres of liquid P be mixed of 7 L of liquid. According to the question, \[x\times \frac{10}{7}+\frac{5}{7}\times 7=x+7\] \[\Rightarrow \]   \[\frac{10x}{7}+5=x+7\] \[\Rightarrow \]   \[10x+35=7x+49\] \[\Rightarrow \]   \[10x-7x=49-35\] \[\Rightarrow \]   \[3x=14\] \[\Rightarrow \]   \[x=\frac{14}{3}=4\frac{2}{3}\text{L}\]


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