A) \[\frac{2412}{7}\,\,{{\text{m}}^{2}}\]
B) \[\frac{2312}{7}\,\,{{\text{m}}^{2}}\]
C) \[\frac{2112}{7}\,\,{{\text{m}}^{2}}\]
D) \[\frac{2012}{7}\,\,{{\text{m}}^{2}}\]
Correct Answer: C
Solution :
Total surface area \[=\pi r\,\,(l+r)=\frac{22}{7}\times 6\times (10+6)=\frac{2112}{7}{{\text{m}}^{2}}\]
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