A) 7
B) 6
C) 5
D) 4
Correct Answer: C
Solution :
On dividing the given number by 56, let k be the quotient. \[\therefore \] Number \[=56\,\,k+29=(8\times 7k+8\times 3+5)=8(7k+3)+5\] \[\therefore \] The given number when divided by 8, gives \[(7k+3)\] as quotient and 5 as remainder. Remark If the first divisor is a multiple of the second divisor the required remainder can be obtained by dividing the remainder by the second divisor. i.e., \[29\div 8\]gives 5 as remainder.
You need to login to perform this action.
You will be redirected in
3 sec
