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SSC Sample Paper Mock Test-11 SSC CGL Tear-II Paper-1

  • question_answer
    What are the factor of \[\left( \frac{1}{3}{{x}^{2}}-2x-9 \right)?\]

    A)  \[\frac{1}{3}(x-9)(x+3)\]

    B)  \[\frac{1}{3}(x-9)(x-3)\]

    C) \[\frac{1}{3}(x+9)(x+3)\]

    D)  \[\frac{1}{3}(x+9)(x-3)\]

    Correct Answer: A

    Solution :

    \[\left( \frac{1}{3}{{x}^{2}}-2x-9 \right)=\frac{({{x}^{2}}-6x-27)}{3}\] \[=\frac{1}{3}[{{x}^{2}}-9x+3x-27]\] \[=\frac{1}{3}[x(x-9)+3(x-9)]\] \[=\frac{1}{3}(x+3)(x-9)\]


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