A) \[\frac{10}{\sqrt{3}}\,\,\text{m}\]
B) \[10\sqrt{3}\]
C) \[\frac{30}{\sqrt{3}}\,\,\text{m}\]
D) \[30\,\,\text{m}\]
Correct Answer: D
Solution :
Let RQ be the height of building, then RQ = 10 m, S be the position of helicopter, then In\[\Delta PQR,\] |
\[\frac{RQ}{PQ}=\tan 30{}^\circ \] |
\[\Rightarrow \] \[PQ=\frac{RQ}{\tan 30{}^\circ }=10\sqrt{3}\] |
In \[\Delta SPQ,\] |
\[\tan 60{}^\circ =\frac{SQ}{PQ}\Rightarrow \frac{SQ}{PQ}=\sqrt{3}\] |
\[SQ=PQ\times \sqrt{3}\] |
\[=10\sqrt{3}\times \sqrt{3}=30\,\,\text{m}\] |
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