A) \[x+y=2\]
B) \[8x+y=9\]
C) \[7x-y=6\]
D) None of these
Correct Answer: C
Solution :
| We have to find locus of the point (h, k) whose image in the line \[2x-y-1=0\] lies on the line\[y=x\]. Now, image of (h, k) in the line \[2x-y-1=0\] is given by, |
| \[\frac{{{x}_{2}}-h}{2}=\frac{{{y}_{2}}-k}{-\,\,1}=-\frac{2\,\,(2h-k-1)}{5}\] |
| \[\Rightarrow \] \[{{x}_{2}}=\frac{-3h+4k+4}{5}\] |
| and \[{{y}_{2}}=\frac{4h+3k-2}{5}\] |
| This point lies on\[y=x\]. |
| Then, |
| \[\frac{-\,\,3\,\,h+4\,\,k+4}{5}=\frac{4\,\,h+3\,\,k-2}{5}\] |
| \[\Rightarrow \] \[7h-k=6\] |
| So, \[7x-y=6\] |
You need to login to perform this action.
You will be redirected in
3 sec
