A) 144 cm
B) \[72\sqrt{2}\,\,\text{cm}\]
C) \[144\sqrt{2}\,\,\text{cm}\]
D) None of these
Correct Answer: C
Solution :
| Length of a diagonal of square \[=\frac{144}{2}=72\,\,\text{cm}\] |
| Let side of square of 'a,' then |
| \[{{a}^{2}}+{{a}^{2}}={{(72)}^{2}}\] |
| \[2{{a}^{2}}={{(72)}^{2}}\] |
| \[\Rightarrow \] \[\sqrt{2a}=72\]\[\Rightarrow \]\[a=\frac{72}{\sqrt{2}}\] |
| \[\therefore \]The perimeter of square |
| \[=4a=4\times \frac{72}{\sqrt{2}}=144\sqrt{2}\,\,\text{cm}\] |
You need to login to perform this action.
You will be redirected in
3 sec
