A) 15 yr
B) 18 yr
C) 20 yr
D) \[16\frac{2}{3}\]yr
Correct Answer: D
Solution :
After 10 yr, |
\[\text{SI}=\frac{1000\times 5\times 10}{100}\]= Rs. 500 |
Principal for 11th year and next |
\[=1000+500\]= Rs. 1500 |
SI = Rs. \[(2000-1500)\] = Rs. 500 |
\[\therefore \] \[T=\frac{SI\times 100}{P\times R}=\frac{500\times 100}{1500\times 5}\] |
\[=\frac{20}{3}\text{yr}=6\frac{2}{3}\text{yr}\] |
\[\therefore \]Total time \[=10+6\frac{2}{3}=16\frac{2}{3}\text{yr}\] |
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