A) \[14\frac{1}{3}\text{days}\]
B) \[15\frac{2}{3}\text{days}\]
C) \[16\frac{1}{3}\text{days}\]
D) \[18\frac{2}{3}\text{days}\]
Correct Answer: A
Solution :
| A's 1 day's work \[=\frac{1}{12}\] |
| B?s 1 day's work \[=\frac{1}{18}\] |
| Part of work done by A and B in first two days |
| \[=\frac{1}{12}+\frac{1}{18}=\frac{3+2}{36}=\frac{5}{36}\] |
| Part of work done by A and B in 14 days \[=\frac{35}{36}\] |
| Remaining work \[=1-\frac{35}{36}=\frac{1}{36}\] |
| Now A will work for 15th day. |
| A will do the \[\frac{1}{36}\]work in\[=\frac{1}{36}\times 12=\frac{1}{3}\]day |
| \[\therefore \]Work will be done in \[14\frac{1}{3}\]days. |
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