SSC Sample Paper Mock Test-12 SSC CGL Tear-II Paper-1

  • question_answer
    Find the diameter of a wheel that makes 113 revolutions to go 2 km 26 decameters. \[\left( \text{Take}\,\,\pi =\frac{22}{7} \right)\]

    A)  \[4\frac{4}{13}\,\,\text{m}\]

    B)  \[6\frac{4}{11}\,\,\text{m}\]

    C)  \[12\frac{4}{11}\,\,\text{m}\]

    D)  \[=\frac{280}{6}-\frac{255}{6}=\frac{25}{6}=4.17\]

    Correct Answer: B

    Solution :

    The distance covered = 2 km 26 decameters
    \[=(2\times 1000+26\times 10)\,\,\text{m}=2260\,\,\text{m}\]
    The distance covered in one revolution
    \[\text{=}\frac{\text{Total}\,\,\text{distance}}{\text{Number}\,\,\text{of}\,\,\text{revolutions}}=\frac{2260}{113}=20\,\,\text{m}\]
    Number of revolutions 113
    Obviously,
    Circumference of wheel \[=20\,\,\text{m}\]
    \[\Rightarrow \] \[\pi \times \] diameter\[=20\,\,\text{m}\]
    \[\Rightarrow \]   Diameter \[=\frac{20}{\pi }=\frac{20\times 7}{22}=\frac{70}{11}=6\frac{4}{11}\,\,\text{m}\]


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