SSC Sample Paper Mock Test-12 SSC CGL Tear-II Paper-1

The perimeters of two squares are 40 cm and 32 cm. The perimeter of a third square whose area is the difference of the areas of the two squares is

A) 24 cm

B) 42 cm

C) 40 cm

D) 20 cm

Correct Answer: A

Solution :

Side of one square \[=\frac{40}{4}=10\,\,\text{cm}\][\[\because \]Perimeter = 4 \[\times \]Side]

Side of other square \[=\frac{32}{4}=8\,\,\text{cm}\]

According to the question,

Area of third square

\[={{(10)}^{2}}-{{(8)}^{2}}=100-64=36\,\text{sq}\,\,\text{cm}\]

\[\therefore \]Side of, third square \[=\sqrt{36}=6\]cm

\[\therefore \]Its perimeter \[=4\times 6=24\]cm