A) 0
B) \[-1\]
C) 2
D) 1
Correct Answer: D
Solution :
As, \[\cos x=1-{{\cos }^{2}}x\] \[={{\sin }^{2}}x\] \[{{\sin }^{8}}x+2{{\sin }^{6}}x+{{\sin }^{4}}x={{(\cos x)}^{4}}+2{{\cos }^{3}}x+{{\cos }^{2}}x\] \[={{({{\cos }^{2}}x+\cos x)}^{2}}\] [from Eq.(i)] \[={{(1)}^{2}}=1\]You need to login to perform this action.
You will be redirected in
3 sec