A) \[6\frac{3}{5}\]
B) \[3\frac{1}{7}\]
C) \[1\frac{5}{12}\]
D) \[1\frac{4}{17}\]
Correct Answer: D
Solution :
| \[x+\frac{1}{1+\frac{1}{3+\frac{1}{4}}}=2\] |
| \[\Rightarrow \] \[x+\frac{1}{1+\frac{1}{(13/4)}}=2\] |
| \[\Rightarrow \] \[x+\frac{1}{1+\frac{4}{13}}=2\] |
| \[\Rightarrow \] \[x+\frac{1}{(17/13)}=2\] |
| \[\Rightarrow \] \[x+\frac{13}{17}=2\] |
| \[\Rightarrow \] \[x=\left( 2-\frac{13}{17} \right)\] |
| \[\Rightarrow \] \[x=\frac{34-13}{17}=\frac{21}{17}=1\frac{4}{17}\] |
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