question_answer

If a pair of perpendicular straight lines drawn through the origin forms an isosceles triangle with the line \[2x+3y=6,\] then area of the triangle so formed is

A) 36/13

B)  12/17  

C)  13/5    

D)  17/13

Correct Answer: A

Solution :

Distance of (0, 0) from the line \[2x+3y-6=0\]is      \[6/\sqrt{4+9}=6/\sqrt{13}.\] The area of the triangle is \[{{(6/\sqrt{13})}^{2}}=36/13\]