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SSC Sample Paper Mock Test-12 SSC CGL Tear-II Paper-1

  • question_answer
    For what value of \[x,\]\[{{x}^{3}}-2{{x}^{2}}-2x-3\] and\[{{x}^{2}}-2x-3\] becomes equal to zero?

    A) 3

    B)  \[-\,\,3\]

    C)  4

    D)  2

    Correct Answer: A

    Solution :

    \[{{x}^{2}}-2x-3={{x}^{2}}-3x+x-3=x\,\,(x-3)+1\,\,(x-3)\]      \[=(x-3)(x+1)\] \[{{x}^{3}}-2{{x}^{2}}-2x-3=\,\,(x-3)({{x}^{2}}+x+1)\] (By synthetic division method) \[\therefore \] HCF of polynomials \[=x-3\] So, value of x = 3 on it will eliminate both the polynomials.


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