A) 2 : 1
B) 1 : 8
C) 1 : 2
D) 8 : 1
Correct Answer: C
Solution :
Case I |
When height \[={{h}_{1}},\]radius \[={{r}_{1}},\] |
Volume of the cone \[{{V}_{1}}=\frac{1}{3}\pi r_{1}^{2}{{h}_{1}}\] |
Case II |
When height \[{{h}_{2}}=2{{h}_{1}},\] radius\[{{r}_{2}}=2{{r}_{1}}\] |
\[\therefore \]Volume of the cone \[{{V}_{2}}=\frac{1}{3}\pi r_{1}^{2}\cdot 2{{h}_{1}}\] |
\[\therefore \]The required ratio = 1 : 2 |
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