A) 10
B) 46
C) 70
D) 90
Correct Answer: A
Solution :
Suppose 1st number is x. |
Then, 2nd number \[=100-x\] |
\[\therefore \] LCM \[\times \] HCF = 1st number \[\times \] 2nd number |
\[495\times 5=x\times (100-x)\] |
\[495\times 5=100x-{{x}^{2}}\] |
\[\Rightarrow \]\[{{x}^{2}}-55x-45x-2475=0\] |
\[(x-45)(x-55)=0\] |
\[x=45\]or \[x=55\] |
Then, difference \[=55-45=10\] |
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