A) \[4\sqrt{2}\,\,\text{cm}\]
B) \[4\sqrt{3}\,\,\text{cm}\]
C) \[6\sqrt{3}\,\,\text{cm}\]
D) \[8\sqrt{2}\,\,\text{cm}\]
Correct Answer: A
Solution :
OA = Diameter of inner circle = 4 cm |
and \[OB=AB-OA=6-4=2\,\,\text{cm}\] |
PQ and AB are two chord of outer circle, |
\[\therefore \] \[OA\times OB=OP\times OQ\] \[(\because OP=OQ)\] |
\[\Rightarrow \] \[4\times 2=O{{P}^{2}}\] |
\[\Rightarrow \] \[OP=2\sqrt{2}\,\,\text{cm}\] |
\[\therefore \] \[PQ=2\times 2\sqrt{2}=4\sqrt{2}\,\,\text{cm}\] |
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