A) 3
B) \[-\,\,3\]
C) 4
D) 2
Correct Answer: A
Solution :
\[{{x}^{2}}-2x-3={{x}^{2}}-3x+x-3=x\,\,(x-3)+1\,\,(x-3)\] \[=(x-3)(x+1)\] \[{{x}^{3}}-2{{x}^{2}}-2x-3=\,\,(x-3)({{x}^{2}}+x+1)\] (By synthetic division method) \[\therefore \] HCF of polynomials \[=x-3\] So, value of x = 3 on it will eliminate both the polynomials.You need to login to perform this action.
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