A) \[9\frac{1}{11}%\]
B) 10%
C) 11%
D) \[11\frac{1}{9}%\]
Correct Answer: A
Solution :
Let length \[=l\] and breadth = b New breadth = z Then, (110% of l)\[\times z=l\times b\] \[\frac{110\,\,l\,\,z}{100}=lb\]\[\Rightarrow \]\[z=\frac{10\,\,b}{11}\] \[\therefore \] Percentage decrease in breadth \[=\left[ \left( b-\frac{10}{11}b \right)\times \frac{1}{b}\times 100 \right]=9\frac{1}{11}%\]You need to login to perform this action.
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