Directions: Study the following graph carefully and answer the questions given below. |
A) 5.14
B) 6.14
C) 2.17
D) 4.17
Correct Answer: D
Solution :
Total production in \[1999=40+35+45+45\] \[+\,40+50=255\] \[\therefore \] Average production in 1999 \[=\frac{255}{6}\] Total production in 2000 \[=45+45+40+55+55+40=280\] Average production in 2000 \[=\frac{280}{6}\] Average difference \[=\frac{280}{6}-\frac{255}{6}=\frac{25}{6}=4.17\] (approx.)You need to login to perform this action.
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