A) 0.4 cm
B) 0.6 cm
C) 0.8 cm
D) 1.0 cm
Correct Answer: B
Solution :
By given condition, \[27\times \]Volume of smaller drops = Volume of bigger drop \[\therefore \] \[27\times \frac{4}{3}\pi \,\,{{r}^{3}}=\frac{4}{3}\pi \,\,{{R}^{3}}\] \[\therefore \] \[27\times {{(0.2)}^{3}}={{R}^{3}}\] \[\Rightarrow \] \[{{(3\times 0.2)}^{3}}={{R}^{3}}\] \[\therefore \] \[R=0.6\,\,\text{cm}\]
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