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SSC Sample Paper Mock Test-13 SSC CGL Tear-II Paper-1

  • question_answer
    If \[{{a}^{4}}+{{b}^{4}}={{a}^{2}}{{b}^{2}},\]then\[({{a}^{6}}+{{b}^{6}})\]is equal to

    A) 0

    B)  1

    C)  \[{{a}^{2}}+{{b}^{2}}\]

    D)  \[{{a}^{2}}+{{b}^{4}}+{{a}^{4}}+{{b}^{2}}\]

    Correct Answer: A

    Solution :

    \[{{a}^{2}}+{{b}^{4}}-{{a}^{2}}{{b}^{2}}=0\]               ...(i) \[\Rightarrow \]\[{{a}^{6}}+{{b}^{6}}={{({{a}^{2}})}^{3}}+{{({{b}^{2}})}^{3}}\] \[=({{a}^{2}}+{{b}^{2}})({{a}^{4}}-{{a}^{2}}{{b}^{2}}+{{b}^{4}})\] \[=({{a}^{2}}+{{b}^{2}})\times 0=0\]           [from Eq.(i)]


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