A) \[32\sqrt{2}\]
B) \[34\]
C) 38
D) \[40\sqrt{2}\]
Correct Answer: B
Solution :
\[\frac{1}{x}=\frac{1}{3+\sqrt{8}}=\frac{3-\sqrt{8}}{(3+\sqrt{8})(3-\sqrt{8})}=\frac{3-\sqrt{8}}{9-8}=3-\sqrt{8}\]\[\therefore \] \[{{x}^{2}}+\frac{1}{{{x}^{2}}}={{\left( x+\frac{1}{x} \right)}^{2}}-2\] \[={{(3+\sqrt{8}+3-\sqrt{8})}^{2}}-2\] \[={{(6)}^{3}}-2=36-2=34\]You need to login to perform this action.
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