A) 50
B) 100
C) 150
D) 200
Correct Answer: C
Solution :
Let the length of train be x metre. \[\therefore \] \[\frac{x}{15}=\frac{x+100}{25}\]\[\Rightarrow \]\[\frac{x}{3}=\frac{x+100}{5}\] \[\Rightarrow \] \[5x=3x+300\] \[\Rightarrow \] \[2x=300\] \[\Rightarrow \] \[x=\frac{300}{2}=150\,\,\text{m}\]You need to login to perform this action.
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