A) \[\frac{a-3b}{a+2b}\]
B) \[\frac{a+3b}{a-2b}\]
C) \[\frac{a+2b}{a-3b}\]
D) \[\frac{a-2b}{a+3b}\]
Correct Answer: C
Solution :
\[\log {{x}^{2}}{{y}^{2}}=a\]\[\Rightarrow \]\[2\log x+2\log y=a\] \[\Rightarrow \]\[\log x-\log y=b\] Solving \[\log x=\frac{a+2b}{4}\]and \[\log y=\frac{a-3b}{4}\] \[\therefore \] \[\frac{\log x}{\log y}=\frac{a+2b}{a-3b}\]You need to login to perform this action.
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