A) \[\frac{3}{4}\]
B) \[\frac{4}{3}\]
C) 0
D) \[\frac{55}{4}\]
Correct Answer: C
Solution :
\[\frac{x}{y}=2\]\[\Rightarrow \]\[x=2y\] \[\Rightarrow \]\[x-2y=0\] ?(i) \[\therefore \]\[5{{x}^{2}}-13xy+6{{y}^{2}}\] \[=5{{x}^{2}}-10xy-3xy+6{{y}^{2}}=5x\,\,(x-2y)-3y\,\,(x-2y)\] \[=(x-2y)(5x-3y)=0\times (5x-3y)=0\]You need to login to perform this action.
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