A) 1.08
B) 5.04
C) 2.16
D) 1.92
Correct Answer: A
Solution :
Let 3.06 = a and 1.98 = b \[\therefore \] Expression\[=\frac{{{a}^{3}}-{{b}^{3}}}{{{a}^{2}}+ab+{{b}^{2}}}\] \[=\frac{(a-b)({{a}^{2}}+ab+{{b}^{2}})}{{{a}^{2}}+ab+{{b}^{2}}}\] \[=a-b=3.06-1.98=1.08\]You need to login to perform this action.
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