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SSC Sample Paper Mock Test-13 SSC CGL Tear-II Paper-1

  • question_answer
    If \[a:b:c=(y-z):(z-x):(x-y),\]then the value of\[ax+by+cz\]is

    A) 1

    B)  3     

    C)  0

    D)  \[-1\]

    Correct Answer: C

    Solution :

    \[\frac{a}{y-z}=\frac{b}{z-x}=\frac{c}{x-y}=k\] \[\Rightarrow \]\[a=k\,\,(y-z);\]\[b=k\,\,(z-x)\]\[\Rightarrow \]\[c=k\,\,(x-y)\] \[\therefore \]\[ax+by+cz=k\] \[(xy-xz+yz-xy+xz-yz)=0\]


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