A) \[x=1\]
B) \[x=-1\]
C) \[x=\frac{1}{2}\]
D) \[x=2\]
Correct Answer: A
Solution :
\[25x-19-[3-\{4x-5\}]=3x-(6x-5)\] \[\Rightarrow \]\[25x-19-[3-4x+5]=3x-6x+5\] \[\Rightarrow \]\[25x-19+4x-8=-3x+5\] \[\Rightarrow \]\[29x+3x=5+27\] \[\Rightarrow \]\[32x=32\]\[\Rightarrow \]\[x=\frac{32}{32}=1\] \[\therefore \]\[x=1\]
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