A) \[3\sqrt{3}\]
B) \[8\sqrt{3}\]
C) \[14+8\sqrt{3}\]
D) \[14\]
Correct Answer: D
Solution :
\[x=7-4\sqrt{3}\] \[\therefore \] \[\frac{1}{x}=\frac{1}{7-4\sqrt{3}}\] \[=\frac{1\,\,(7+4\sqrt{3})}{(7+4\sqrt{3})(7-4\sqrt{3})}\] \[=\frac{7+4\sqrt{3}}{49-48}=7+4\sqrt{3}=14\] \[\therefore \] \[=\frac{1}{4}\left( \frac{1}{4}+\frac{1}{4} \right)=\frac{7}{48}\]You need to login to perform this action.
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