A) Rs. 1500
B) Rs. 1200
C) Rs. 1100
D) Rs. 1000
Correct Answer: D
Solution :
Let the sum be Rs. x. |
r = 10%, n = 3yr |
SI \[=\frac{x\times r\times n}{100}\] |
SI \[=\frac{x\times 10\times 3}{100}=\frac{3}{10}x\] |
\[\text{CI}=\left[ {{\left( 1+\frac{r}{100} \right)}^{n}}-1 \right]x=\left[ {{\left( 1+\frac{10}{100} \right)}^{3}}-1 \right]x\] |
\[=\left[ {{\left( \frac{11}{10} \right)}^{3}}-1 \right]x=\left( \frac{1331}{1000}-1 \right)x=\frac{331}{1000}x\] |
\[=\frac{331}{1000}x-\frac{3}{10}x=31\] |
\[\Rightarrow \]\[\frac{(331-300)}{1000}x=31\Rightarrow \frac{31}{1000}x=31\] |
\[\Rightarrow \] \[x=1000\] |
Sum = Rs. 1000 |
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