A) 13 : 14
B) 14 : 13
C) 10 : 11
D) 11 : 10
Correct Answer: A
Solution :
\[\frac{x}{y}=\frac{3}{1}\]\[\Rightarrow \]\[\frac{{{x}^{3}}}{{{y}^{3}}}=\frac{27}{1}\] \[\Rightarrow \]\[\frac{{{x}^{3}}-{{y}^{3}}}{{{x}^{3}}+{{y}^{3}}}=\frac{27-1}{27+1}\][By componendo and dividendo] \[=\frac{26}{28}=\frac{13}{14}\]You need to login to perform this action.
You will be redirected in
3 sec