A) 5 m
B) 10 m
C) 12 m
D) 12.5 m
Correct Answer: B
Solution :
Let the length \[=l\,\,\text{m}\]and breadth \[=b\,\,\text{m}\] |
\[\therefore \] \[2\,\,(l+b)=28\] |
\[\Rightarrow \] \[l+b=14\] ...(i) |
\[lb=48\] ...(ii) |
Now, \[{{(l-b)}^{2}}={{(l+b)}^{2}}-4lb={{(14)}^{2}}-4\times 48\] |
\[=196-192=4\] |
\[\Rightarrow \] \[l-b=2\] ?(iii) |
\[l=8,\,\,b=6\] |
\[\therefore \] Diagonal \[=\sqrt{{{8}^{2}}+{{6}^{2}}}=10\,\,\text{m}\] |
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