A) \[25{}^\circ \]
B) \[35{}^\circ \]
C) \[65{}^\circ \]
D) \[40{}^\circ \]
Correct Answer: A
Solution :
In \[\Delta BCD,\] \[\angle BCD=65{}^\circ \] and \[\angle BDC=90{}^\circ \] \[\angle CBA=180{}^\circ -(\angle BCD+\angle CDB)\] \[=180{}^\circ -(65{}^\circ +90{}^\circ )=180{}^\circ -155{}^\circ =25{}^\circ \]You need to login to perform this action.
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