SSC Sample Paper Mock Test-15 SSC CGL Tear-II Paper-1

  • question_answer
    A and B can complete a piece of work in 9 and 12 days, respectively. If they work for a day alternately, starting with A, in how many days will the work be completed?

    A) 10

    B)  \[10\frac{1}{4}\]

    C)  \[10\frac{1}{2}\]          

    D)  \[10\frac{3}{4}\]

    Correct Answer: B

    Solution :

    Part of the work done by A and B together in 2 days
    \[=\frac{1}{9}+\frac{1}{12}=\frac{4+3}{36}=\frac{7}{36}\]
    Part of the work done in first 10 days
    \[=5\times \frac{7}{36}=\frac{35}{36}\]
    Remaining work \[=1-\frac{35}{36}=\frac{1}{36}\]
    Now, it is turn off A
    \[\therefore \] Time taken by A in doing the remaining part of the work \[=\frac{1}{36}\times 9=\frac{1}{4}\]days
    \[\therefore \] Required time \[=10\frac{1}{4}\]days


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