A) 4
B) 5
C) 6
D) 8
Correct Answer: B
Solution :
\[\frac{{{x}^{2}}-x+1}{{{x}^{2}}+x+1}=\frac{2}{3}\] \[\Rightarrow \]\[\frac{{{x}^{2}}+1-x}{{{x}^{2}}+1+x}=\frac{2}{3}\] On dividing numerator and denominator by x, we get \[\frac{\left( x+\frac{1}{x} \right)-1}{\left( x+\frac{1}{x} \right)+1}=\frac{2}{3}\] \[\Rightarrow \] \[3\left( x+\frac{1}{x} \right)-3=2\left( x+\frac{1}{x} \right)+2\] \[\Rightarrow \] \[x+\frac{1}{x}=2+3=5\]
You need to login to perform this action.
You will be redirected in
3 sec
