question_answer

A mixture contains wine and water in the ratio 3 : 2 and another mixture contains them in the ratio 4 : 5. How many litres of the latter must be mixed with 3 L of the former so that the resulting mixture may contain equal quantities of wine and water?

A)  \[5\frac{2}{5}\,\,\text{L}\]

B)  \[5\frac{2}{3}\,\,\text{L}\]

C)  \[4\frac{1}{2}\,\,\text{L}\]

D)  \[3\frac{3}{4}\,\,\text{L}\]

Correct Answer: A

Solution :

By the rule of allegation \[\therefore \] Required ratio \[=\frac{1}{18}:\frac{1}{10}=5:9=3:\frac{9}{5}\times 3=3:\frac{2}{5}\]